Get the last ten business days in a Unix shell script

Shell script to get the last 10 weekdays and run some task for each date over an element array.

#!/usr/bin/bash
n=10
today=$(date +'%Y-%m-%d')
for ((d=1; n>0; d++))
do
    # Adjust this next line to get the date format you require, e.g. +'%Y%m%d'
    date=$(date --date "$today -$d day")
    nday=$(date --date "$today -$d day" +'%w')
    weekdays_date=$(date --date "$today -$d day" +'%Y%m%d')
    if [[ $nday > 0 && $nday < 6 ]]
    then
        declare -a arr=("element1" "element2" "element3")
        # Iterate over the all element for each weekdays_date
        for el in "${arr[@]}"
        do 
           echo "Run process for date: ${weekdays_date}, element: ${el}"
        done 
        
        # Adjust this next line to output whatever you really need
        #echo "n=$n, d=$d, nday=$nday, date=$date: WEEKDAY"
        echo " "
        : $((n--))
    fi
done